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// you can combine the two as follows: string s11 = s3.Insert(s3.IndexOf("Training"), "excellent "); Console.WriteLine("s11: {0}\n", s11); } static void Main( ) { Tester t = new Tester( ); t.Run( ); } } }

TF = 40645(s + r + btt) In order to locate a successor record, we start from the last data record and ignore the index We have to determine whether serial reading can be done sequentially or whether we have to go to another area We can expect to have to go to the over ow area in proportion to the ratio of records to be found there, o /nm , but in the main le we only have to read a new block 1/Bfr times An estimate is then

The output looks like this:

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in order to ensure that all the free space on the page is contiguous Thus, the ability to move records on a page becomes very important The most exible organization for variable-length records is to maintain a directory of slots for each page, with a record o set, record length pair per slot The rst component (record o set) is a pointer to the record, as shown in Figure 78; it is the o set in bytes from the start of the data area on the page to the start of the record Deletion is readily accomplished by setting the record o set to -1 Records can be moved around on the page because the rid, which is the page number and slot number (that is, position in the directory), does not change when the record is moved; only the record o set stored in the slot changes

A more precise case analysis has to consider all the possibilities which exist and consider the locations of the predecessor and of the successor record The six cases we can distinguish are illustrated using the record numbers of Fig 3-9 The process is owcharted in Fig 3-11 The result, after simpli cation, becomes Eq 3-41 Path Choices for Next Record We consider again block-anchored over ow records, and begin with the most likely case: a The current record is in a main data le block and the successor record is in the same block, and hence already available in a memory bu er (eg, the current record is 111, 112, 121, ) b The current record is the last one in the block, there were no insertions, and the successor record is in a following block on the same cylinder c The current record is the last one in the block, and there have been no insertions, but the record is in a new block on another cylinder Given that there are blocks per cylinder, and the le begins at a new cylinder, this would happen between records 3 and ( + 1)1, 2 3 and (2 + 1)1, once for each cylinder occupied by the le

s5 copied from s2: ABCD String s3 is 94 characters long. The 5th character is r s3:Liberty Associates, Inc. provides custom .NET development, on-site Training and Consulting Ends with Training : False Ends with Consulting : True The first occurrence of Training in s3 is 71 s10: Liberty Associates, Inc. provides custom .NET development, on-site excellent Training and Consulting s11: Liberty Associates, Inc. provides custom .NET development, on-site excellent Training and Consulting

d The current record is the last one in the block, but there has been an insertion, and the successor record will be in an over ow block (the current record is 113 or 123) e The current record is an inserted record, and the successor is found following the chain to another over ow block on the same cylinder (current record is 1101 or 1111) f The current record is an inserted record, and to get to the successor record a new data block has to be read (current record is 1102, 1103, or 1112)

The Length property returns the length of the entire string, and the index operator ([]) is used to access a particular character within a string. Just like arrays, the index numbering in a string starts at zero.

Console.WriteLine( "\nString s3 is {0} characters long. ", s5.Length); Console.WriteLine( "The 5th character is {0}\n", s3[4]);

Sec 3-3

Here s the output:

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